Question:easy

Which of the following is an example of fractional order reaction ?

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Acetaldehyde decomposition has an experimental rate law of order 3/2.
Updated On: Oct 1, 2026
  • \(2\text{H}_2\text{O}_2\text{(g)}⟶2\text{H}_2\text{O}\text{(l)}+\text{O}_2\text{(g)}\)
  • \(\text{H}_2\text{(g)}+\text{I}_2\text{(g)}⟶2\text{HI}\text{(g)}\)
  • \(\text{CH}_3\text{CHO}\text{(g)}⟶\text{CH}_4\text{(g)}+\text{CO}\text{(g)}\)
  • \(2\text{NO}\text{(g)}+2\text{H}_2\text{(g)}⟶\text{N}_2\text{(g)}+2\text{H}_2\text{O}\text{(l)}\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Look for the rate law:
Order comes from experiment, so recall the measured rate laws.
Hydrogen peroxide decomposition: rate $= k[\text{H}_2\text{O}_2]$, order 1.
Hydrogen with iodine: rate $= k[\text{H}_2][\text{I}_2]$, order 2.
Nitric oxide with hydrogen: rate $= k[\text{NO}]^2[\text{H}_2]$, order 3.
Acetaldehyde decomposition: rate $= k[\text{CH}_3\text{CHO}]^{3/2}$, order $1.5$.

Step 2: Pick the odd one:
Three of the four orders are integers. The acetaldehyde reaction is the lone fractional case, caused by a radical chain mechanism with several steps.

Final Answer:
Option (C). \[ \boxed{\text{CH}_3\text{CHO} \to \text{CH}_4 + \text{CO} \text{ (C)}} \]
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