Step 1: Use the definition:
Ambident = two different donor atoms, one used at a time.
Step 2: Test each ligand:
en: N,N both N. $\text{Cl}^-$: one donor. EDTA: uses several donors together (polydentate). SCN: S or N.
Step 3: Pick:
Option D.
Final Answer:
SCN can bind through S or N, so it is ambident.
\[ \boxed{\text{(D) }\text{SCN}} \]