Question:medium

Which of the following is a Fittig reaction?

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Wurtz = Alkyl; Fittig = Aryl; Wurtz-Fittig = Mixed.
Updated On: Jun 19, 2026
  • $C_{6}H_{5}Br + CH_{3}Br + 2Na \xrightarrow{dry~ether} C_{6}H_{5}CH_{3} + 2NaBr$
  • $2C_{2}H_{5}Br + 2Na \xrightarrow{dry~ether} C_{2}H_{5}C_{2}H_{5} + 2NaBr$
  • $2CH_{3}Br + 2Na \xrightarrow{dry~ether} CH_{3}CH_{3} + 2NaBr$
  • $2C_{6}H_{5}Br + 2Na \xrightarrow{dry~ether} C_{6}H_{5}C_{6}H_{5} + 2NaBr$
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Understanding the Question:
The question asks to identify the specific named organic reaction involving sodium and aryl/alkyl halides in dry ether.

Step 3: Detailed Explanation:

- Wurtz Reaction: $2 \text{ molecules of alkyl halide} + \text{Na} \rightarrow \text{Higher alkane}$. (Options B and C)
- Wurtz-Fittig Reaction: $1 \text{ alkyl halide} + 1 \text{ aryl halide} + \text{Na} \rightarrow \text{Alkylarene}$. (Option A)
- Fittig Reaction: $2 \text{ molecules of aryl halide} + \text{Na} \rightarrow \text{Biaryl (Biphenyl)}$. (Option D)
In option D, two molecules of bromobenzene react with sodium to form biphenyl.

Step 4: Final Answer:

Option D represents a Fittig reaction.
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