Step 1: Recall the reaction.
A Grignard reagent \(R-MgBr\) adds to methanal (formaldehyde, HCHO). After hydrolysis it gives a primary alcohol \(R-CH_2OH\).
Step 2: Note the carbon count.
The product alcohol has one carbon more than the alkyl group \(R\) of the Grignard reagent, because the carbon of methanal is added.
Step 3: Work backward from the target alcohol.
Remove the \(-CH_2OH\) part of the required alcohol. The leftover group tells us which \(R-MgBr\) is needed.
Step 4: Identify R.
For the given target, the leftover group is methyl, so the Grignard reagent is \(CH_3MgBr\).
Step 5: Conclusion.
\(CH_3MgBr\) reacting with HCHO followed by hydrolysis gives the desired alcohol.
\[ \boxed{CH_3MgBr} \]