Question:medium

Which of the following functions has derivative equal to \( \cos x \)?

Show Hint

Be very careful with negative signs in trigonometric derivatives and integrals.
The derivative of \( \sin x \) is \( \cos x \), but the integral of \( \sin x \) is \( -\cos x \).
Memorizing these pairs in a tabular format prevents silly mistakes under exam pressure.
Updated On: Jun 3, 2026
  • \( \sin x \)
  • \( -\sin x \)
  • \( \tan x \)
  • \( \sec x \)
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
This problem requires identifying a fundamental trigonometric derivative. Finding a function whose derivative is known is the basic definition of an antiderivative or indefinite integral.
Step 2: Key Formula or Approach:
We evaluate the standard differentiation formulas for each of the core trigonometric choices presented in the options: - $\frac{d}{dx}(\sin x) = \cos x$ - $\frac{d}{dx}(\cos x) = -\sin x$ - $\frac{d}{dx}(\tan x) = \sec^2 x$
Step 3: Detailed Explanation:
Let's check the derivatives of the given options to find which one results exactly in $\cos x$: - Option (A): The derivative of the standard sine function is $\frac{d}{dx}(\sin x) = \cos x$. This perfectly matches our target derivative condition. - Option (B): The derivative of $-\sin x$ yields $\frac{d}{dx}(-\sin x) = -\cos x$, which features an incorrect negative sign. - Option (C): The derivative of $\tan x$ is $\sec^2 x$. - Option (D): The derivative of $\sec x$ is $\sec x \tan x$. Therefore, the function that has a derivative equal to $\cos x$ is $\sin x$, making option (A) correct.
Step 4: Final Answer:
The function whose derivative equals $\cos x$ is $\sin x$.
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