Question:medium

Which of the following expressions will give the area of the region bounded by the curve $y = x^2$ and the line $y = 16$?

Show Hint

If integrated along the $x$-axis, the area would be $\int_{-4}^{4} (16 - x^2) \, dx = 2 \int_{0}^{4} (16 - x^2) \, dx$. Always verify whether the options integrate with respect to $x$ or $y$ to choose the matching formulation.
  • $\int_{0}^{4} 2x \, dx$
  • $2 \int_{0}^{4} 2x \, dx$
  • $\int_{0}^{16} y \, dy$
  • $2 \int_{0}^{16} \sqrt{y} \, dy$
Show Solution

The Correct Option is D

Solution and Explanation

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