Problem:
Determine which equation lacks a real root.
Solution:
A quadratic equation \(ax^2 + bx + c = 0\) has real roots if the discriminant \(D = b^2 - 4ac \geq 0\).
Consider the equation \(x^2 + 1 = 0\). Here, \(a = 1\), \(b = 0\), and \(c = 1\).
Calculate the discriminant:
\[D = 0^2 - 4 \times 1 \times 1 = -4\]
Since \(D = -4 < 0\), this equation has no real roots.
Answer:
\[\boxed{x^2 + 1 = 0}\]