Question:medium

Which of the following coordination compounds exhibits geometrical isomerism?

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Geometrical isomerism in octahedral complexes occurs in \( \text{MA}_4\text{B}_2 \) or \( \text{MA}_2\text{B}_2 \) types, where cis and trans arrangements are possible. Check the coordination number and ligand types to identify isomerism.
Updated On: Feb 19, 2026
  • \( [\text{Co}(\text{NH}_3)_6]\text{Cl}_3 \)
  • \( [\text{Co}(\text{NH}_3)_4\text{Cl}_2]\text{Cl} \)
  • \( [\text{Co}(\text{NH}_3)_5\text{Cl}]\text{Cl}_2 \)
  • \( [\text{Co}(\text{Cl})_4]^{2-} \)
Show Solution

The Correct Option is B

Solution and Explanation


Geometrical isomerism in coordination compounds arises from distinct spatial arrangements of ligands, typically in square planar or octahedral geometries. Ligands can be adjacent (cis) or opposite (trans). Evaluating each option:
- (1) \( [\text{Co}(\text{NH}_3)_6]\text{Cl}_3 \): An octahedral complex with six identical \( \text{NH}_3 \) ligands. No geometrical isomerism is possible.
- (2) \( [\text{Co}(\text{NH}_3)_4\text{Cl}_2]\text{Cl} \): An octahedral complex (formula \( \text{MA}_4\text{B}_2 \)) with four \( \text{NH}_3 \) and two \( \text{Cl} \) ligands. The two \( \text{Cl} \) ligands can occupy cis (adjacent) or trans (opposite) positions, demonstrating geometrical isomerism.
- (3) \( [\text{Co}(\text{NH}_3)_5\text{Cl}]\text{Cl}_2 \): An octahedral complex (formula \( \text{MA}_5\text{B} \)) with one \( \text{Cl} \) ligand. With only one of a particular ligand type, different spatial arrangements are not possible, thus no geometrical isomerism.
- (4) \( [\text{Co}(\text{Cl})_4]^{2-} \): A tetrahedral complex with four identical \( \text{Cl} \) ligands. Tetrahedral complexes with identical ligands do not exhibit geometrical isomerism due to the inherent symmetry.
Consequently, \( [\text{Co}(\text{NH}_3)_4\text{Cl}_2]\text{Cl} \) is the compound exhibiting geometrical isomerism.
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