Question

Which of the following compounds is formed when chlorine reacts with dry slake lime \(\text{Ca(OH)}_2\) ?

• A. \(\text{CaOCl}_2\)
• B. \(\text{CaO}_2\text{Cl}_2\)
• C. \(\text{CaOCl}\)
• D. \(\text{CaCl}_2\)

Hint:

Chlorine and dry slaked lime give bleaching powder, CaOCl2.

Answer 1

The Correct Option is A

Step 1: Reaction:
Dry $\text{Ca(OH)}_2$ absorbs $\text{Cl}_2$ at about room temperature.

Step 2: Equation:
$\text{Ca(OH)}_2 + \text{Cl}_2 \to \text{CaOCl}_2 + \text{H}_2\text{O}$.

Step 3: Name:
The product is bleaching powder (calcium chlorohypochlorite). That is option (A).

Final Answer:
Bleaching powder forms. \[ \boxed{\text{(A) }\text{CaOCl}_2} \]