Question:medium

Which of the following compound has high melting point?

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The greater the molecular weight and the length of the carbon chain in organic molecules, the higher the melting point, due to stronger intermolecular forces.
Updated On: Mar 28, 2026
  • 1-Bromopropane
  • 1-Bromopropane
  • 1-Bromobutane
  • 1-Bromo-2-methylpropane
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The Correct Option is C

Solution and Explanation

Melting Point of Organic Compounds (Haloalkanes):
Melting points are influenced by:
  • Molecular Symmetry: Increased symmetry enhances crystal lattice packing, resulting in higher melting points.
  • Branching: Branched isomers typically exhibit lower melting points than their unbranched counterparts.
  • Molecular Weight: Higher molecular weight generally correlates with higher melting points.

Analysis of Options:

Option 1: 1-Bromopropane
  • Straight-chain, small molecule. Less symmetrical compared to some alternatives.
  • Expected to have a moderate melting point.

Option 2: 1-Bromopropane
  • This is a duplicate of Option 1.

Option 3: 1-Bromobutane
  • Possesses a longer carbon chain and greater molecular weight than bromopropane.
  • However, its symmetry is limited. Its melting point is higher than propyl derivatives but not the maximum among the options.

Option 4: 1-Bromo-2-methylpropane
  • Highly branched structure, leading to inefficient packing in the crystal lattice.
  • Irregular molecular shape results in a lower melting point.

Key Consideration:
For haloalkanes, molecular symmetry plays a crucial role in determining melting point, often more so than molecular weight alone. The straight-chain structure of 1-Bromobutane allows for superior packing compared to branched isomers, contributing to its elevated melting point.

Conclusion: Option 3: 1-Bromobutane
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