Question:medium

Which of the following complexes will exhibit maximum attraction to an applied magnetic field?

Show Hint

Magnetic properties depend on the number of unpaired electrons. The higher the unpaired electrons, the stronger the attraction to a magnetic field.
Updated On: Jan 13, 2026
  • \( [Zn(H_2O)_6]^{2+} \)
  • \( [Co(H_2O)_6]^{2+} \)
  • \( [Co(en)_3]^{3+} \)
  • \( [Ni(H_2O)_6]^{2+} \)
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Assess Magnetic Behavior
Paramagnetic complexes are characterized by the presence of unpaired electrons.
An increased number of unpaired electrons correlates with a heightened attraction to a magnetic field.
Step 2: Evaluate Electron Configurations
\( Zn^{2+} \) (\( d^{10} \)) exhibits 0 unpaired electrons, classifying it as diamagnetic.
\( Co^{2+} \) (\( d^7 \)) possesses 3 unpaired electrons, indicating paramagnetism.
\( Co^{3+} \) (\( d^6 \), low spin) has 0 unpaired electrons, thus being diamagnetic.
\( Ni^{2+} \) (\( d^8 \)) contains 2 unpaired electrons, rendering it paramagnetic, though with a lower magnetic attraction than \( Co^{2+} \).
Conclusion: \( [Co(H_2O)_6]^{2+} \) demonstrates the strongest paramagnetism due to its 3 unpaired electrons.
Was this answer helpful?
0