Understanding the Concept:
Bond order:
\[
BO = \frac{N_b - N_a}{2}
\]
Step 1: N$_2$ configuration.
Bond order = 3
Removing electron from bonding orbital:
\[
BO = 2.5 \Rightarrow \text{decrease}
\]
Step 2: F$_2$ configuration.
Bond order = 1
Removing electron from antibonding orbital:
\[
BO = 1.5 \Rightarrow \text{increase}
\]
Step 3: Final Answer.
\[
\boxed{\text{Decrease in N$_2$, increase in F$_2$}}
\]