Question:medium

Which of the following arrangements does not represent the correct order of the property stated against it?

Show Hint

The paramagnetic behavior of an ion is directly linked to the number of unpaired electrons. More unpaired electrons lead to a stronger paramagnetic behavior.
Updated On: Mar 28, 2026
  • \( \text{V}^{2+}<\text{Cr}^{2+}<\text{Mn}^{2+}<\text{Fe}^{2+} \): Paramagnetic behaviour
  • \( \text{Ni}^{2+}<\text{Co}^{2+}<\text{Fe}^{2+}<\text{Mn}^{2+} \): Ionic size
  • \( \text{Co}^{3+}<\text{Fe}^{3+}<\text{Cr}^{3+}<\text{Sc}^{3+} \): Stability in aqueous solution
  • \( \text{Sc}<\text{Ti}<\text{Cr}<\text{Mn} \): Number of oxidation states
Show Solution

The Correct Option is A

Solution and Explanation

The number of unpaired electrons in an ion's electronic configuration dictates its paramagnetic behavior. The configurations and their corresponding unpaired electrons are: \( \text{V}^{2+}: 3d^3 \) (3 unpaired electrons), \( \text{Cr}^{2+}: 3d^4 \) (4 unpaired electrons), \( \text{Mn}^{2+}: 3d^5 \) (5 unpaired electrons), and \( \text{Fe}^{2+}: 3d^6 \) (4 unpaired electrons). Consequently, the correct order of paramagnetic behavior, based on the number of unpaired electrons, is \( \text{V}^{2+}<\text{Cr}^{2+}<\text{Fe}^{2+}<\text{Mn}^{2+}. \) Therefore, Option (1) does not accurately represent this order.

Final Answer: \[ \boxed{\text{V}^{2+}<\text{Cr}^{2+}<\text{Mn}^{2+}<\text{Fe}^{2+}}. \]

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