Question:medium

Which of the following are APs? If they form an AP, find the common difference d and write three more terms.
(i) 2, 4, 8, 16, . . . .
(ii) \(2, \frac{5}{2},3,\frac{7}{2}\), . . . .
(iii) – 1.2, – 3.2, – 5.2, – 7.2, . . . .
(iv) – 10, – 6, – 2, 2, . . .
(v) 3, \(3 + \sqrt{2} , 3 + 3\sqrt{2} , 3 + 3 \sqrt{2}\) . . . .
(vi) 0.2, 0.22, 0.222, 0.2222, . . . .
(vii) 0, – 4, – 8, –12, . . . .
(viii) \(\frac{-1}{2}, \frac{-1}{2}, \frac{-1}{2}, \frac{-1}{2}\), . . . .
(ix) 1, 3, 9, 27, . . . .
(x) a, 2a, 3a, 4a, . . . .
(xi) a, \(a^2, a^3, a^4,\)  . . . .
(xii) \(\sqrt{2}, \sqrt{8} , \sqrt{18} , \sqrt {32}\) . . . .
(xiii) \(\sqrt {3}, \sqrt {6}, \sqrt {9} , \sqrt {12}\) . . . . .
(xiv) \(1^2 , 3^2 , 5^2 , 7^2\), . . . .
(xv) \(1^2 , 5^2, 7^2, 7^3\), . . . .

Updated On: Jan 13, 2026
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Solution and Explanation

(i) The sequence 2, 4, 8, 16... is analyzed. The differences between consecutive terms are: \(a_2 - a_1 = 4 - 2 = 2\), \(a_3 - a_2 = 8 - 4 = 4\), and \(a_4 - a_3 = 16 - 8 = 8\). Since the difference \(a_{k+1} - a_k\) is not constant, these numbers do not form an Arithmetic Progression (A.P.).


(ii) The sequence 2, \( \frac{5}{2}, 3, \frac{7}{2} \) is analyzed. The differences between consecutive terms are: \(a_2-a_1 = \frac{5}{2}-2 = \frac{1}{2}\), \(a_3 - a_2 = 3- \frac{5}{2} = \frac{1}{2}\), and \(a_4 - a_3 = \frac{7}{2} - 3 = \frac{1}{2}\). Since the difference \(a_{k+1} - a_k\) is constant, these numbers form an A.P. with a common difference d = \( \frac{1}{2} \). The next three terms are \(a_5 = \frac{7}{2} + \frac{1}{2} = 4\), \(a_6 = 4 + \frac{1}{2} = \frac {9}{2}\), and \(a_7 = \frac{9}{2} + \frac{1}{2} = 5\).


(iii) The sequence - 1.2, - 3.2, - 5.2, - 7.2... is analyzed. The differences between consecutive terms are: \(a_2 - a_1 = ( - 3.2) - ( - 1.2) = - 2\), \(a_3 - a_2 = ( - 5.2) - ( - 3.2) = - 2\), and \(a_4 - a_3 = ( - 7.2) - ( - 5.2) = - 2\). Since the difference \(a_{k+1} - a_k\) is constant, these numbers form an A.P. with a common difference d = - 2. The next three terms are \(a_5 = - 7.2 - 2 = - 9.2\), \(a_6 = - 9.2 - 2 = - 11.2\), and \(a_7 = - 11.2 - 2 = - 13.2\).


(iv) The sequence - 10, - 6, - 2, 2... is analyzed. The differences between consecutive terms are: \(a_2 - a_1 = ( - 6) - ( - 10) = 4\), \(a_3 - a_2 = ( - 2) - ( - 6) = 4\), and \(a_4 - a_3 = (2) - ( - 2) = 4\). Since the difference \(a_{k+1} - a_k\) is constant, these numbers form an A.P. with a common difference d = 4. The next three terms are \(a_5 = 2 + 4 = 6\), \(a_6 = 6 + 4 = 10\), and \(a_7 = 10 + 4 = 14\).


(v) The sequence 3, \(3+\sqrt{2} , 3+ 2\sqrt{2} , 3 + 3 \sqrt{2}\), ..... is analyzed. The differences between consecutive terms are: \(a_2 - a_1 = 3 + \sqrt{2}-3 = \sqrt{2}\), \(a_3 - a_2 = 3 + 2 \sqrt{2} - 3 - \sqrt{2}= \sqrt{2}\), and \(a_4 - a_3 = 3 + 3 \sqrt{2} - 3 - 2 \sqrt{2}= \sqrt{2}\). Since the difference \(a_{k+1}-a_k\) is constant, these numbers form an A.P. with a common difference d = \(\sqrt{2}\). The next three terms are \(a_5 = 3 + 3 \sqrt{2} + \sqrt{2} = 3 + 4 \sqrt{2}\), \(a_6 = 3 + 4 \sqrt{2} + \sqrt{2} = 3 + 5 \sqrt{2}\), and \(a_7 = 3 + 5 \sqrt{2} + \sqrt{2} = 3 + 6 \sqrt{2}\).


(vi) The sequence 0.2, 0.22, 0.222, 0.2222... is analyzed. The differences between consecutive terms are: \(a_2 - a_1 = 0.22 - 0.2 = 0.02\), \(a_3 - a_2 = 0.222 - 0.22 = 0.002\), and \(a_4 - a_3 = 0.2222 - 0.222 = 0.0002\). Since the difference \(a_{k+1} - a_k\) is not constant, these numbers do not form an A.P.


(vii) The sequence 0, - 4, - 8, - 12... is analyzed. The differences between consecutive terms are: \(a_2-a_1 = ( - 4) - 0 = - 4\), \(a_3-a_2 = ( - 8) - ( - 4) = - 4\), and \(a_4 - a_3 = ( - 12) - ( - 8) = - 4\). Since the difference \(a_{k+1}-a_k\) is constant, these numbers form an A.P. with a common difference d = - 4. The next three terms are a+(5 - 1)d = -16, a+(6 - 1)d = -20, and a+(7 - 1)d = -24.


(viii) This sequence is an A.P. with a common difference of 0. Therefore, the next three terms will be the same as the previous ones, i.e., \(-\frac{1}{2}\).


(ix) The differences between the first three terms are 9 - 3 = 6 and 3 - 1 = 2. Since 6 ≠ 2, \(a_3 - a_2 eq a_2 - a_1\). Therefore, the given numbers do not form an A.P.


(x) This sequence is an A.P. with a common difference d = 2a - a = a and the first term is a. The next three terms are a + (5 - 1)d = 5a, a + (6 - 1)d = 6a, and a + (7 - 1)d = 7a.


(xi) This sequence is not an A.P. because the difference between consecutive terms is not constant.


(xii) This sequence is an A.P. with a common difference d = \(\sqrt{2}\) and the first term a = \(\sqrt{2}\). The next three terms are a + (5 - 1)d = \(5\sqrt{2}=\sqrt{50}\), a + (6 - 1)d = \(\sqrt{72}\), and a + (7 - 1)d = \(\sqrt{98}\).


(xiii) This sequence is not an A.P. because the difference between consecutive terms is not constant.


(xiv) This sequence is not an A.P. because the difference between consecutive terms is not constant.


(xv) This sequence is an A.P. with a common difference d = 52 - 1 = 24 and the first term a = 1. The next three terms are a + (5 - 1)d = 97, a + (6 - 1)d = 121, and a + (7 - 1)d = 145.

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