Step 1: Mechanism:
One step, back-side attack, so steric crowding at the carbon matters most.
Step 2: Compare:
Number of alkyl groups on the carbon: methyl 0, ethyl 1, isopropyl 2, tert-butyl 3. More groups mean more crowding and a slower reaction.
Step 3: Answer:
Methyl bromide in option (A) reacts fastest.
Final Answer:
Methyl bromide is the fastest SN2 substrate.
\[ \boxed{\text{(A) }\text{CH}_3\text{-Br}} \]