Step 1: Count carbons:
Possible chain lengths equal the sum of the carbons of the two groups joined.
Step 2: List:
$2+2=4$ (butane), $3+3=6$ (hexane), $2+3=5$ (pentane).
Step 3: Missing:
A three-carbon product would need a 1-carbon fragment, which is not present. So propane is not obtained, option (B).
Final Answer:
Propane cannot be formed.
\[ \boxed{\text{(B) }\text{Propane}} \]