The stability of hydrides is influenced by factors like bond strength and the nature of the bonds between hydrogen and the accompanying element. In this case, we're evaluating the stability of hydrides: HF, BeH2, NH3, and LiH. Let's analyze them for stability:
HF is a covalent hydride with strong hydrogen bonds due to high electronegativity of fluorine. The strong H-F bond contributes to its stability. Hence, HF is quite stable.
BeH2 is predominantly covalent but forms polymeric chains through bridging hydrogen atoms. Its small size and the nature of its bonding lead to lower stability compared to other covalent hydrides. Thus, BeH2 is less stable.
NH3 is a covalent hydride with strong N-H bonds due to nitrogen's high electronegativity and the lone pair that allows hydrogen bonding. This gives NH3 stability.
LiH is ionic in nature, formed by the transfer of an electron from lithium to hydrogen. The strong ionic bond provides this compound with significant stability.
From this analysis, it is clear that BeH2 is the least stable hydride due to weak polymeric nature and the absence of strong bonds like hydrogen bonds or ionic character. Therefore, the correct answer is BeH2.
A group 15 element forms \( d\pi - d\pi \) bond with transition metals. It also forms a hydride, which is the strongest base among the hydrides of other group members that form \( d\pi - d\pi \) bonds. The atomic number of the element is …….