Step 1: Orientation:
Boron attaches to the terminal carbon, $\text{CH}_2$, which has less steric hindrance.
Step 2: Replace B by OH:
After peroxide oxidation, the terminal carbon carries $-\text{OH}$: $\text{CH}_3\text{CH}_2\text{CH}_2\text{OH}$, propan-1-ol.
Final Answer:
Propan-1-ol is formed, option (C).
\[ \boxed{\text{Propan-1-ol}} \]