Step 1: Two Tests:
Test 1: is the OH carbon attached directly to a benzene ring? Test 2: does that carbon carry two hydrogens (primary)?
Step 2: Apply:
Only $\text{C}_6\text{H}_5\text{CH}_2\text{OH}$ passes both. Option (B) passes test 1 but its carbon has one H, so it is secondary. Options (C) and (D) have a vinyl group, not a ring.
Step 3: Answer:
Option (A).
Final Answer:
Option (A).
\[ \boxed{\text{(A) } \text{C}_6\text{H}_5\text{CH}_2\text{OH}} \]