Step 1: Compare bond lengths
I-Br is longer than Br-Cl, Br-F and Cl-F.
Step 2: Relate to stability
Longer bond means lower bond energy, so the compound decomposes most readily. That is IBr, option (A).
Final Answer:
IBr, with the longest and weakest bond, is least stable, option (A).
\[ \boxed{\text{IBr}} \]