The total number of electrons in an ion is determined by its atomic number and charge:
- \( \text{Na}^+ \) has 10 electrons (Na: atomic number 11, loses 1 electron).
- \( \text{Al}^{3+} \) has 10 electrons (Al: atomic number 13, loses 3 electrons).
Therefore, \( \text{Na}^+ \) and \( \text{Al}^{3+} \) have the same number of electrons, making this pair correct. Let's analyze other pairs:
- \( \text{O}^{2-} \) has 10 electrons (O: atomic number 8, gains 2 electrons), and \( \text{F}^- \) has 10 electrons (F: atomic number 9, gains 1 electron). This pair also has the same number of electrons.
- \( \text{Mg}^{2+} \) has 10 electrons (Mg: atomic number 12, loses 2 electrons), while Ar has 18 electrons. This pair does not have the same number of electrons.
- \( \text{P}^{3-} \) has 18 electrons (P: atomic number 15, gains 3 electrons), and Ar has 18 electrons. This pair has the same number of electrons.
The correct answer is \( \text{Mg}^{2+} \) and Ar.