Step 1: What the reaction needs:
A carbon bonded to the halogen that is sp3 hybridised and open to backside attack.
Step 2: Test each halide:
Ethyl bromide, isobutyl bromide (the figure shows $\text{CH}_3\text{-CH(CH}_3)\text{-CH}_2\text{-Br}$) and benzyl bromide all have sp3 carbons bearing Br. Bromobenzene has the halogen on an sp2 ring carbon, so it is unreactive. Answer (C).
Final Answer:
Bromobenzene.
\[ \boxed{\text{(C)}} \]