Which alkene on ozonolysis gives CH3CH2CHO and 

CH3CH2CH = CHCH2CH3
CH3CH2CH = CHCH3

To determine which alkene gives the specified products on ozonolysis, we first need to understand the reaction and its outcomes:
Ozonolysis is a reaction where an alkene reacts with ozone (O3) to form a molozonide, which rearranges to produce a carbonyl compound. In this reaction, the C=C double bond of the alkene is cleaved, producing aldehydes and/or ketones as products.
The given products are CH3CH2CHO (propanal) and acetone \((\text{CH}_3\text{COCH}_3)\).
To find the correct alkene, let's consider the possible structures:
Based on these observations, the structure should look something like CH3CH2CH=CHCH3. This matches with one of the options given, aligning with both propanal and acetone formation:
When ozonolysis occurs:
Thus, the correct answer is: