Question:hard
When two wires are connected in the two gaps of a meter bridge, the balancing point is obtained at a distance of \(48.4\) cm from the left end of the bridge wire. If the wire in the left gap is stretched so that its resistance increases by \(3.2\%\) and the wire in the right gap is stretched so that its resistance increases by \(10\%\), then the new balancing length from the left end of the bridge wire is nearly
When two wires are connected in the two gaps of a meter bridge, the balancing point is obtained at a distance of \(48.4\) cm from the left end of the bridge wire. If the wire in the left gap is stretched so that its resistance increases by \(3.2\%\) and the wire in the right gap is stretched so that its resistance increases by \(10\%\), then the new balancing length from the left end of the bridge wire is nearly
Show Hint
In a meter bridge,
\[
\frac{R}{S}=\frac{l}{100-l}.
\]
If resistances are modified, first calculate the new ratio
\[
\frac{R'}{S'},
\]
and then use the balance condition again to find the new balancing length.
Updated On: Jul 29, 2026
- \(33.3\) cm
- \(66.6\) cm
- \(44.4\) cm
- \(55.5\) cm
Show Solution
The Correct Option is C
Solution and Explanation
Was this answer helpful?
0
Top Questions on Meter Bridge
- The resistance per centimeter of a meter bridge wire is \( r \), with \( X \, \Omega \) resistance in the left gap. Balancing length from the left end is at 40 cm with 25 \( \Omega \) resistance in the right gap. Now the wire is replaced by another wire of \( 2r \) resistance per centimeter. The new balancing length for the same settings will be at:
- JEE Main - 2024
- Physics
- Meter Bridge
- In a metre-bridge, when a resistance of $2 \, \Omega$ is in the left gap and the unknown resistance in the right gap, the balance length is found to be 40 cm. On shunting the unknown resistance with $2 \, \Omega$, the balance length changes by:
- JEE Main - 2024
- Physics
- Meter Bridge
- In case of meter bridge experiment balance length for $2\Omega$ and $3\Omega$ is $\ell$ and for $x\Omega$ and $3\Omega$ is $(\ell + 10)$ cm. Find $x$.
- JEE Main - 2026
- Physics
- Meter Bridge
A meter bridge with two resistances \( R_1 \) and \( R_2 \) as shown in figure was balanced (null point) at 40 cm from the point \( P \). The null point changed to 50 cm from the point \( P \), when a \( 16\,\Omega \) resistance is connected in parallel to \( R_2 \). The values of resistances \( R_1 \) and \( R_2 \) are
- JEE Main - 2026
- Physics
- Meter Bridge
- Want to practice more? Try solving extra ecology questions todayView All Questions