When two sound waves having amplitudes 3 and 5 units are superimposed, find the ratio of maximum to minimum intensity of the resultant wave.
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This is a standard CET problem. Remember the shortcut: Ratio \(= \left( \frac{a_1 + a_2}{a_1 - a_2} \right)^2\). For \(3\) and \(5\), the sum is \(8\) and difference is \(2\). \(8/2 = 4\), and \(4^2 = 16\). Result is \(16:1\).