Question:medium

When two resistances \(P\) and \(Q\) are connected in the left and right gaps of a meter bridge respectively, the balancing point is obtained at a distance greater than \(25\,cm\). If the resistance \(P\) is increased by \(5\Omega\), the balancing point shifts by \(10\,cm\). After that, if the resistance \(Q\) is halved, the balancing point further shifts by \(15\,cm\), then the initial value of \(P\) is:

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For meter bridge questions always use \[ \frac{R_1}{R_2} = \frac{l}{100-l} \] and write a new equation after every change in the circuit.
Updated On: Jun 18, 2026
  • \(5\Omega\)
  • \(15\Omega\)
  • \(10\Omega\)
  • \(20\Omega\)
Show Solution

The Correct Option is C

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