Question:medium
When phenol is treated with NaOH, CO_2 (heat), and then acidified, what results?
When phenol is treated with NaOH, CO_2 (heat), and then acidified, what results?
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The Kolbe-Schmitt reaction involves phenol, NaOH, CO\(_2\), and acidification to form salicylic acid.
Updated On: Jul 3, 2026
- Benzoic acid
- Salicylic acid
- Benzene
- Anisole
Show Solution
The Correct Option is B
Solution and Explanation
Treating phenol with sodium hydroxide first converts it to sodium phenoxide, a far better nucleophile than phenol itself. Heating this phenoxide with carbon dioxide under pressure lets the ring attack the carbon of CO\(_2\) at the position next to the oxygen, installing a carboxylate group there, this is the Kolbe-Schmitt reaction. Acidifying afterward just protonates that carboxylate and the phenoxide, giving salicylic acid, option (B).
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