Question

When magnetic flux changes from $6.5 \times 10^{-2}$ Wb to $11 \times 10^{-2}$ Wb and the change in current is 0.03 A, the coefficient of mutual inductance will be ______.

• A. 1.0 H
• B. 1.2 H
• C. 1.5 H
• D. 1.8 H

Hint:

Mutual inductance ($M$) is simply the ratio of "how much flux is produced" to "how much current caused it". Just divide the net change in flux by the net change in current!

Answer 1

The Correct Option is C

Step 1: Understanding the Concept:
The relation between magnetic flux ($\phi$) and current ($I$) in mutual induction is $\Delta \phi = M \Delta I$.

Step 2: Formula Application:
$M = \frac{\Delta \phi}{\Delta I}$.

Step 3: Explanation:
$\Delta \phi = (11 - 6.5) \times 10^{-2} = 4.5 \times 10^{-2}$ Wb. $\Delta I = 0.03$ A $= 3 \times 10^{-2}$ A. $M = \frac{4.5 \times 10^{-2}}{3 \times 10^{-2}} = \frac{4.5}{3} = 1.5$ H.

Step 4: Final Answer:
The coefficient of mutual inductance is 1.5 H.