Question

When excess of chlorine is used in the chlorination of methane find the major product obtained.

• A. Chloromethane
• B. Dichloromethane
• C. Trichloromethane
• D. Tetrachloromethane

Hint:

With excess chlorine every hydrogen is replaced and the final product is carbon tetrachloride.

Answer 1

The Correct Option is D

Step 1: Think about reagent ratio
With limited Cl$_2$ the mono-chloro product dominates. With excess Cl$_2$ each product is chlorinated again.

Step 2: Final stage
After four substitutions no C-H bond remains, so $\text{CCl}_4$ forms. This is option (D).

Final Answer:
Tetrachloromethane is the major product with excess chlorine, option (D). \[ \boxed{\text{CCl}_4} \]