When both trains meet, they are at the same point. Therefore, both trains are equidistant from Chennai.

Question

Series Expansion $ n^6 + \frac{1}{2} n^4 + \frac{1}{3} n^2 + \cdots + \frac{1}{n} C_n + 1 \quad n \to \infty $

Answer 1

Step 1: Number the letters, A = 1 up to Z = 26, so S = 19.

Step 2: The gap between letters grows by one each time: 1, 2, 3, 4, so the next gap is 5.

Step 3: Subtract this gap from S's position: $ 19 - 5 = 14 $.

Step 4: Position 14 is the letter N.
\[ \boxed{N} \]

When both trains meet, they are at the same point. Therefore, both trains are equidistant from Chennai.

The Correct Option is A

Solution and Explanation

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