When a parallel combination of 2 capacitors of 100 pF each is connected across a series combination of 2 capacitors of 200 pF each, the effective capacitance is
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For series capacitors of equal value, the result is the value divided by the number of capacitors (\(200/2 = 100\)). For parallel, just multiply by the number (\(100 \times 2 = 200\)).