Question

When \(0.5\,\text{\AA}\) X-rays strike a material, the photoelectrons from the K-shell are observed to move in a circular path of radius \(23\,\text{mm}\) in a magnetic field of \(2 \times 10^{-2}\,\text{T}\), perpendicular to the direction of emission of photoelectrons. What is the binding energy of K-shell electrons?

• A. \(3.5\,\text{keV}\)
• B. \(6.2\,\text{keV}\)
• C. \(2.9\,\text{keV}\)
• D. \(5.5\,\text{keV}\)

Hint:

Magnetic field gives momentum directly: \[ p=eBr \] Then use photoelectric equation.

Answer 1

The Correct Option is B