Question

What would be the magnification (more than 1 / less than 1 / equal to 1) if the object is placed between F and 2F of the above lens?

Hint:

Memorize the image formation table for a convex lens. Object at 2F \(\rightarrow\) Image at 2F, \(m=1\). Object between F and 2F \(\rightarrow\) Image beyond 2F, \(m>1\). Object beyond 2F \(\rightarrow\) Image between F and 2F, \(m<1\).

Answer 1

Step 1: Understanding the Concept:
Magnification (\( m \)) for a lens is the ratio of image distance to object distance: \( m = \frac{v}{|u|} \).
Step 2: Detailed Explanation:
When an object is placed between \( F \) and \( 2F \) of a convex lens:
1. The image formed is real, inverted, and located beyond \( 2F \).
2. Since the image is further from the lens than the object (\( v>2f \) and \( f<|u|<2f \)), it follows that \( v>|u| \).
3. Therefore, the magnification \( m = \frac{v}{|u|} \) is greater than 1.
Step 3: Final Answer:
The magnification is more than 1.