Question:medium

What shall be the arithmetic mean of all the distinct numbers that can be obtained by rearranging the digits in 1421 including itself?

Show Hint

For permutations with repetition, sum of all numbers = (sum of digits in each position) $\times$ (111...1).
Updated On: Jun 15, 2026
  • 3333
  • 2448
  • 2222
  • 2442
  • 2592
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
Digits: 1, 4, 2, 1. Total distinct permutations $= \frac{4!}{2!} = 12$.
Step 2: Key Formula or Approach:
Sum of all numbers $= (\text{Sum of unique digits}) \times (\text{Permutations per digit in a place}) \times (1111)$.
Mean $= \frac{\text{Total Sum}}{\text{Total Permutations}}$.
Step 3: Detailed Explanation:
Sum of digits in any place:
Digit 4 appears $3!/2! = 3$ times.
Digit 2 appears $3!/2! = 3$ times.
Digit 1 appears $3! = 6$ times.
Sum per place $= (4 \times 3) + (2 \times 3) + (1 \times 6) = 12 + 6 + 6 = 24$.
Total Sum $= 24(10^3) + 24(10^2) + 24(10^1) + 24(10^0) = 24 \times 1111 = 26664$.
Mean $= \frac{26664}{12} = 2222$.
Step 4: Final Answer:
The arithmetic mean is 2222.
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