(i) C2H2
Structure of C2H2 (ethyne):
H — C ≡ C — H
• One C≡C triple bond consists of 1 σ bond and 2 π bonds
• Two C—H single bonds consist of 2 σ bonds
Total number of σ bonds = 3
Total number of π bonds = 2
(ii) C2H4
Structure of C2H4 (ethene):
H2C = CH2
• One C=C double bond consists of 1 σ bond and 1 π bond
• Four C—H single bonds consist of 4 σ bonds
Total number of σ bonds = 5
Total number of π bonds = 1
Final Answer:
C2H2 → σ = 3, π = 2
C2H4 → σ = 5, π = 1
\(O - O\) bond length in \(H _2 O _2\) is X than the \(O - O\) bond length in \(F _2 O _2\)The \(O - H\) bond length in \(H _2 O _2\)is Y than that of the\(O - F\) bond in \(F _2 O _2\)Choose the correct option for \(\underline{X} and \underline{Y}\) from those given below :
The correct order of bond enthalpy \(\left( kJ mol ^{-1}\right)\) is :