Question:medium

What is the total number of donor atoms present in Tetracyanonickelate(II) ion?

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"Tetra" = 4. Monodentate ligands contribute 1 donor atom each.
Updated On: May 14, 2026
  • 2
  • 4
  • 6
  • 1
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
Donor atoms are the atoms in ligands that directly donate electron pairs to the central metal ion.
Step 2: Key Formula or Approach:
Identify the ligands and their denticity.
$[\text{Ni}(\text{CN})_4]^{2-}$.
Step 3: Detailed Explanation:
The name Tetracyanonickelate(II) implies a nickel ion bonded to four cyano ($\text{CN}^-$) groups.
Cyanide ($\text{CN}^-$) is a monodentate ligand, meaning it has one donor atom (typically Carbon in these complexes).
With four such ligands, there are $4 \times 1 = 4$ donor atoms.
Step 4: Final Answer:
The total number of donor atoms is 4.
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