Step 1: Quick Bound:
$10^{-4} < 5\times10^{-4} < 10^{-3}$, so pH lies between 3 and 4. That already rules out (A) and (C).
Step 2: Exact Value:
$\log 5 = 0.699$. So $\text{pH} = 4 - 0.699 = 3.301$.
Step 3: Last Option:
3.725 would need $[\text{H}^+] = 1.9\times10^{-4}$, not the given value. The answer is (B).
Final Answer:
Option (B), 3.301.
\[ \boxed{\text{(B) } 3.301} \]