Question:medium

What is the packing efficiency in fcc lattice?

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For fcc lattices, remember: number of atoms per unit cell = 4, edge length \(a = 2\sqrt{2}r\), and packing efficiency = 74%.
Updated On: Jun 19, 2026
  • 74%
  • 52%
  • 78%
  • 68%
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The Correct Option is A

Solution and Explanation

Step 1: Grasping the fcc arrangement.
A face-centered cubic lattice hosts atoms at all eight corners and the centers of all six faces.

Step 2: Atoms per unit cell.

Corner atoms each supply 1/8: 8 × 1/8 = 1 atom. Face atoms each supply 1/2: 6 × 1/2 = 3 atoms. Total = 4 atoms per unit cell.

Step 3: Linking radius to edge length.

In fcc, the face diagonal equals 4r. Edge length a = 4r / √2 = 2√2 r.

Step 4: Volume of atoms inside the cell.

Four atomic spheres occupy 4 × (4/3)πr³ = (16/3)πr³.

Step 5: Total unit cell volume.

a³ = (2√2 r)³ = 16√2 r³.

Step 6: Packing efficiency calculation.

Efficiency = (atom volume / cell volume) × 100% = [(16/3)πr³ / (16√2 r³)] × 100% = 74%.

Step 7: Final statement.

The fcc lattice achieves 74% packing efficiency, the maximum among cubic structures.
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