Step 1: Rank the acids:
Acid strength: $\text{HOCl} < \text{HClO}_2 < \text{HClO}_3 < \text{HClO}_4$. The more oxygen atoms on Cl, the stronger the acid.
Step 2: Compute for HOCl:
Let Cl be $x$: $+1 + x - 2 = 0$, so $x = +1$.
Step 3: Rule out others:
$-1$ occurs in chlorides, not oxoacids. $-3$ is not possible for chlorine. $+3$ is in $\text{HClO}_2$, which is stronger than HOCl.
Final Answer:
Option (A), $+1$.
\[ \boxed{+1 \text{ (A)}} \]