Question

What is the number of tetrahedral voids present in \(0.5\) mole of compound forming hcp structure?

• A. \(1.223\times 10^{23}\)
• B. \(3.628\times 10^{23}\)
• C. \(4.487\times 10^{23}\)
• D. \(6.022\times 10^{23}\)

Hint:

An hcp lattice has 2 tetrahedral voids per atom, so find the number of atoms first.

Answer 1

The Correct Option is D

Step 1: Rule:
Tetrahedral voids are twice the number of close-packed atoms.

Step 2: Count:
Half a mole of atoms is $3.011\times10^{23}$. Doubling it gives $6.022\times10^{23}$, which is exactly one mole of voids.

Step 3: Answer:
Option (D).

Final Answer:
Option (D). \[ \boxed{\text{(D) } 6.022\times 10^{23}} \]