Question:medium

What is the equivalent depth of water contained in a soil profile of 1 m deep, if the mass wetness of the upper 0.4 m is 15% and that of the lower 0.6 m is 25%? Assume a bulk density of 1200 kg/m$^3$ in the upper layer and 1400 kg/m$^3$ in the lower layer.

Show Hint

Always convert mass wetness (\( w \)) to volumetric water content (\( \theta \)) first, using the relation \( \theta = w \cdot \text{Specific Gravity of bulk soil} \).
Specific gravity \( = \frac{\rho_b}{\rho_w} \).
  • 0.072
  • 0.210
  • 0.350
  • 0.282
Show Solution

The Correct Option is D

Solution and Explanation

Was this answer helpful?
0