Question:medium

What is the determinant of an identity matrix of any order \(n\)?

Show Hint

The determinant of any {identity matrix} is always \(1\), regardless of its size. Also, multiplying any matrix by an identity matrix leaves the matrix unchanged.
Updated On: Mar 16, 2026
  • \(0\)
  • \(1\)
  • \(n\)
  • \(-1\)
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Question:
The question asks for the determinant of an identity matrix, denoted as \(I_n\), for any size \(n \times n\).
Step 2: Key Formula or Approach:
A key property of determinants is that for any upper triangular, lower triangular, or diagonal matrix, the determinant is simply the product of the elements on its main diagonal.
Step 3: Detailed Explanation:
An identity matrix \(I_n\) is a special type of diagonal matrix. Its main diagonal consists entirely of 1s, and all other elements are 0s.
For example, the \(3 \times 3\) identity matrix is:
\[ I_3 = \begin{bmatrix} 1 & 0 & 0
0 & 1 & 0
0 & 0 & 1 \end{bmatrix} \] To find its determinant, we apply the rule for diagonal matrices and multiply the elements on the main diagonal.
\[ \det(I_n) = \underbrace{1 \times 1 \times 1 \times \dots \times 1}_{n \text{ times}} \] The product of any number of 1s is always 1.
\[ \det(I_n) = 1 \] Step 4: Final Answer:
The determinant of an identity matrix of any order \(n\) is always 1.
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