What is the Crystal Field Stabilization Energy (CFSE) for a d⁸ metal ion in an octahedral field?

Question

Identify the homoleptic complex(es) that is/are low spin.
[(A)] \([\text{Fe(CN)}_5\text{NO}]^{2-}\)
[(B)] \([\text{CoF}_6]^{3-}\)
[(C)] \([\text{Fe(CN)}_6]^{4-}\)
[(D)] \([\text{Co(NH}_3)_6]^{3+}\)
[(E)] \([\text{Cr(H}_2\text{O)}_6]^{2+}\)
Choose the correct answer from the options given below:

Answer 1

Crystal Field Stabilization Energy (CFSE) is influenced by both the electronic configuration and the ligand field strength (either strong or weak). Strong field ligands result in low-spin complexes, whereas weak field ligands lead to high-spin complexes.

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CFSE for strong field ligands (low spin): −1.2Δ₀ + 2P

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CFSE for weak field ligands (high spin): −0.8Δ₀ − 0.8Δ₀

Firm 2	Cooperate	Compete
Firm 1	5, 5	0, 10
Compete	10,0	2, 2

What is the Crystal Field Stabilization Energy (CFSE) for a d⁸ metal ion in an octahedral field?

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Solution and Explanation

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