Step 1: Idea:
Compute pOH first, then pH, then the hydrogen ion concentration.
Step 2: Steps:
\[ \text{pOH} = -\log(0.08) = 1.097 \]
\[ \text{pH} = 14 - 1.097 = 12.903 \]
\[ [\text{H}^+] = 10^{-12.903} = 1.25\times10^{-13}\ \text{mol/L} = 0.125\times10^{-12}\ \text{mol/L} \]
Only option B has this value. The strong base means a tiny acid concentration, so options A and C are impossible.
Final Answer:
$[\text{H}^+] = 0.125\times10^{-12}$ mol/L, which is option (B).
\[ \boxed{0.125\times10^{-12}\ \text{mol/L}} \]