Question:medium

What is the approximate unit weight of water used in hydraulic calculations?

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Remember: Water → $9.81 \, \text{kN/m}^3$ (standard value).
Updated On: Mar 17, 2026
  • $9.81 \, \text{kN/m}^3$
  • $1.0 \, \text{kN/m}^3$
  • $100 \, \text{kN/m}^3$
  • $0.98 \, \text{kN/m}^3$
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
Unit weight (\(\gamma\)) is the weight of a substance per unit volume.
It is the product of the density (\(\rho\)) and the acceleration due to gravity (\(g\)).
Step 2: Key Formula or Approach:
\[ \gamma_w = \rho_w \times g \] Standard density of water (\(\rho_w\)) = \(1000\text{ kg/m}^3\).
Standard gravity (\(g\)) = \(9.81\text{ m/s}^2\).
Step 3: Detailed Explanation:
\[ \gamma_w = 1000\text{ kg/m}^3 \times 9.81\text{ m/s}^2 = 9810\text{ N/m}^3 \] To convert to kilo-Newtons (\(kN\)):
\[ \gamma_w = \frac{9810}{1000} = 9.81\text{ kN/m}^3 \] Step 4: Final Answer:
The approximate unit weight is \(9.81\text{ kN/m}^3\).
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