Always remember the IUPAC priority sequence for rings: The principal functional group gets position 1, followed by numbering to minimize the substituent locant set, then alphabetical ordering.
Step 1: Understand the figure.
The figure shows a seven membered carbon ring (cycloheptane) that carries an -OH group, an ethyl group, and a methyl group. We must give its IUPAC name.
Step 2: Find the main functional group.
The -OH group has the highest priority here. So the ring is named as a cycloheptanol, and the carbon holding the -OH is numbered 1.
Step 3: Number to get lowest locants.
We number around the ring in the direction that gives the smaller numbers to the two side groups. This gives positions 3 and 6.
Step 4: Place the groups.
The ethyl group sits at position 3 and the methyl group sits at position 6.
Step 5: Order the names alphabetically.
Ethyl comes before methyl in the alphabet, so we write ethyl first.
Step 6: Write the final name.
Putting it together gives 3-Ethyl-6-methyl cycloheptanol, which is option 2.
\[ \boxed{\text{3-Ethyl-6-methyl cycloheptanol}} \]
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