Question

What is action of \(\text{CH}_3\text{ONa}\) on \(\text{CH}_3\text{CH}_2\text{Br}\)
\(\text{CH}_3\text{ONa}+\text{CH}_3\text{CH}_2\text{Br}\rightarrow\) ?

• A. Formation of \(\text{CH}_3\text{OCH}_2\text{CH}_3+\text{NaBr}\)
• B. Formation of \(\text{CH}_3\text{OH}+\text{NaBr}\)
• C. Formation of \(\text{CH}_3\text{CH}_2\text{OH}\)
• D. Formation of \((\text{CH}_3)_2\text{O}\)

Hint:

This is the Williamson ether synthesis.

Answer 1

The Correct Option is A

Step 1: Bond formed
The methoxide oxygen attacks the carbon bearing Br and displaces bromide.

Step 2: Result
Methyl ethyl ether forms. Option (A).

Final Answer:
Ethyl methyl ether. \[ \boxed{\text{(A)}\ CH_3OCH_2CH_3 + NaBr} \]