\(\frac 13\)
\(\frac 14\)
\(\frac {1}{12}\)
\(\frac 12\)
To solve the question of what fraction of one edge-centred octahedral void lies in one unit cell of an FCC (face-centered cubic) structure, we need to understand the geometry and arrangement of octahedral voids in this type of crystal lattice.
Therefore, the correct answer is \(\frac{1}{4}\), meaning one-fourth of an edge-centered octahedral void lies within one unit cell of an FCC lattice.