Given:
Mass of nitrogen gas, m = 2.0 × 10−2 kg
Rise in temperature, ΔT = 45 °C = 45 K
Molecular mass of N2 = 28 g mol−1 = 0.028 kg mol−1
Gas constant, R = 8.3 J mol−1 K−1
The gas is heated at constant pressure.
Step 1: Calculate number of moles of nitrogen
n = m / M
n = (2.0 × 10−2) / 0.028
n = 0.714 mol
Step 2: Write expression for heat supplied at constant pressure
Heat supplied:
Q = n Cp ΔT
For a diatomic gas (like N2) at room temperature:
Cp = 7/2 R
Cp = (7/2) × 8.3 = 29.05 J mol−1 K−1
Step 3: Calculate the heat supplied
Q = 0.714 × 29.05 × 45
Q ≈ 9.33 × 102 J
Final Answer:
The amount of heat required is
Q ≈ 9.3 × 102 J
Match List-I with List-II.
| List-I | List-II |
| (A) Heat capacity of body | (I) \( J\,kg^{-1} \) |
| (B) Specific heat capacity of body | (II) \( J\,K^{-1} \) |
| (C) Latent heat | (III) \( J\,kg^{-1}K^{-1} \) |
| (D) Thermal conductivity | (IV) \( J\,m^{-1}K^{-1}s^{-1} \) |
In the given cycle ABCDA, the heat required for an ideal monoatomic gas will be:

The pressure of a gas changes linearly with volume from $A$ to $B$ as shown in figure If no heat is supplied to or extracted from the gas then change in the internal energy of the gas will be Is
