Question:easy

Waves having a velocity 10m/s, strike a stationary boat near the sea shore. The distance between two consecutive crests of the waves is 40m. After how many second, the consecutive waves strike the boat?

Show Hint

The time between consecutive crests is the period, which equals wavelength divided by wave speed.
Updated On: Oct 1, 2026
  • \(8\) s
  • \(6\) s
  • \(4\) s
  • \(2\) s
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Think of the motion.
The wave moves 10 m each second. The next crest is 40 m behind the first.

Step 2: Find the delay.
Time for the gap of 40 m to pass the boat is $40/10 = 4$ s.

Final Answer:
Option (C). \[ \boxed{4\text{ s}} \]
Was this answer helpful?
0